The solution of the differential equation sinx+cosxdy+cosx−sinxdx=0 is
exsinx+cosx+c=0
eysinx+cosx=c
excosx−sinx=c
eysinx−cosx=c
(sinx+cosx)dy+(cosx−sinx)dx=0∫dy=∫sinx−cosxsinx+cosxdx Put cosx+sinx=t⇒y=−∫dtt=−lnt+lnc⇒y=lncsinx+cosx⇒ey=csinx+cosx⇒ey(sinx+cosx)=c