Questions
The solution to the differential equation is
Unlock the full solution & master the concept.
Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
y =0
b
cx2−y=sin−1x
c
cx−y=sin−1c
d
y=x2−1−sin−1x2−1x
Ready to Test Your Skills?
Check Your Performance Today with our Free Mock Tests used by Toppers!detailed solution
Correct option is A
Given equation is sinxdydx−y=dydx⇒y=xdydx−sin−1dydxAgain differentiating we getdydx=dydx+xd2ydx2−11−dydx2d2ydx2⇒d2ydx2=0 or x=11−dydx2⇒dydx=c or dydx2=1−1x2using, dydx=c in given equation we get y=cx−sin−1cAlso for particular value of c = 0,y = 0 is also a solution.Finally using dydx2=1−1x2 in (i) we get i.e., y=x2−1−sin−1x2−1x
Similar Questions
Want to Improve your productivity
talk to our academic experts now !!
speak to our academic counsellor
access to India's best teachers with a record of producing top rankers year on year.
+91
we will send an otp for verification
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions