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Questions  

 The solution of differential equation xdxydyxdyydx=1+x2y2x2y2 is 

a
x2−y2+x−y+C
b
x2−y2+x2+y2+C
c
x2−y2+1+x2−y2=cx+yx2−y2
d
x2−y2+1+x2−y2=cx−yx2+y2

detailed solution

Correct option is C

Put x=rsec⁡θ y=rtan⁡θ⇒drsec⁡θdθ=1+r2∫dr1+r2=∫sec⁡θdθln⁡r+1+r2=ln⁡|sec⁡θ+tan⁡θ|+ln⁡|c|⇒x2−y2+1+x2−y2=∣c(x+y)x2−y2

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