The solution of differential equation xdy−ydxx2+y2+tan−1xy3(xdy+ydx)=0 is
tan−1yx=ke−xy
−12tan−1yx2+xy+c
tan−1xy=kexy
−12tan−1yx2−xy+c
dtan−1yxtan−1yx3+d(xy)=0 Integrating both sides −12tan−1yx2+xy=c