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Q.

The solution of differential equation xdyy2exy+ex/y=ydxex/y−y2exy , is

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a

xy=logex+λ

b

x2/y=logex/y+λ

c

xy=logex/y+λ

d

xy2=logex/y+λ

answer is C.

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Detailed Solution

xdyy2exy+ex/y=ydxex/y−y2exy⇒ex/y(xdy−ydx)=−exy(xdy+ydx)y2⇒ex/yydx+xdyy2=exy(xdy+ydx)⇒∫ex/ydxy=∫exyd(xy)⇒ex/y+c=exy⇒xy=log⁡ex/y+c
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