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Questions  

 The solution of differential equation xdyy2exy+ex/y=ydxex/yy2exy , is 

a
xy=logex+λ
b
x2/y=logex/y+λ
c
xy=logex/y+λ
d
xy2=logex/y+λ

detailed solution

Correct option is C

xdyy2exy+ex/y=ydxex/y−y2exy⇒ex/y(xdy−ydx)=−exy(xdy+ydx)y2⇒ex/yydx+xdyy2=exy(xdy+ydx)⇒∫ex/ydxy=∫exyd(xy)⇒ex/y+c=exy⇒xy=log⁡ex/y+c

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