Download the app

Questions  

 The solution of the differential equation x2dydxcos1xysin1x=1 When y1 as x is 

a
y=sin(1x)−cos(1x)
b
y=x+1xsin(1x)
c
y=cos(1x)+sin(1x)
d
y=x+1xcos(1x)

detailed solution

Correct option is A

dydx−yx2tan⁡1x=−sec⁡1x⋅1x2 I. F=e∫-1x2tan1xdx=eln sec1x=sec⁡1x Solution of the D.E is ysec⁡1x=−∫sec2⁡1x⋅1x2dxysec⁡1x=tan⁡1x+c........(1) Given y→−1  and x→∞-sec1∞=tan1∞+c  -sec0=tan0+c c=−1substituting  in (1)ysec⁡1x=tan⁡1x-1y=sin⁡1x−cos⁡1x

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

The solution of differential equation ydx+x+x2ydy=0 is


phone icon
whats app icon