The solution of the differential equation 1−x2sin−1xdy+ydx=0 is
ysec−1x=c
ysin−1x=c
xsin−1y=c
xsec−1y=c
The given equation can be rewritten as dx1−x2sin−1x+dyy=0
⇒∫dx1−x2sin−1x+∫dyy=lnc⇒lnsin−1x+lny=lnc⇒ysin−1x=c