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The solution of the differential equation $\sqrt{1 - x^{2}} \sin^{- 1} x d y + y d x = 0$ is

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ysec−1x=c

ysin−1x=c

xsin−1y=c

xsec−1y=c

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detailed solution

Correct option is B

The given equation can be rewritten as dx1−x2sin−1x+dyy=0 ⇒∫dx1−x2sin−1⁡x+∫dyy=ln⁡c⇒ln⁡sin−1⁡x+ln⁡y=ln⁡c⇒ysin−1⁡x=c

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The solution of the differential equation 1−x2sin−1xdy+ydx=0 is

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The solution of the differential equation $\sqrt{1 - x^{2}} \sin^{- 1} x d y + y d x = 0$ is