Solution of the differential equation xsinyxdy=ysinyx−xdx is
logx=cosyx+c
logy=cosyx+c
logx=cosxy+c
none
We have dydx=ysinyx−xxsinyx put y=Vx So that dydx=V+xdVdx Hence, V+xdVdx=VsinV−1sinV=V−1sinV⇒xdVdx=−1sinV⇒∫dxx+∫sinVdV=c⇒logx−cosV=c⇒logx=cosyx+c