The solution of differential equation 3x1−x2y2dydx+2x2−1y3=ax3 is
x3=ay+cy1−x2
y3=ax+cx1−x2
x3=ax+cx1−x2
y3=ay+cx1−x2
Put y3=v⇒3y2dydx=dvdx⇒dvdx+2x2−1x1−x2v=ax21−x2 I. F=1x1−x2 G.S. is v IF=∫Q.IFdxy3x1-x2=∫ax21-x21x1-x2dx G.S is y3=αx+cx1−x2