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Questions  

 The solution of differential equation xy3(1+cosx)ydx+xdy=0 is 

a
y=x3+2xsinx+xcosx−2sinx+c
b
x33+2cosx−xsinx+c
c
x33+x2sinx−2xsinx+cosx+c
d
x22y2=x33+x2sinx+2xcosx−2sinx+c

detailed solution

Correct option is D

dydx+y3(1+cos⁡x)−yx=0−1y3dydx+1y2x=(1+cos⁡x) Put +1y2=u⇒−2y3dydx=dudx12dudx+1xu=1+cos⁡xdudx+2xu=2(1+cos⁡x) I. F=e2∫1xdx=x2 G.S is 1y2x2=∫2(1+cos⁡x)x2dxx22y2=∫x2dx+∫x2cos⁡xdxx22y2=x33+x2sinx+2xcosx-2sinx+c

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