The solution of differential equation 1−xy+x2y2dx=x2dy is
tanxy=logcx
xy=tanlogcx
x+y=xytanxy+c
Given equation is 1−xy+x2y2dx=x2dy⇒1+x2y2dx=x(ydx+xdy)⇒ydx+xdy1+x2y2=dxx⇒d(xy)1+(xy)2=dxx Integrating on both sides ⇒∫d(xy)1+(xy)2=∫dxx⇒tan−1(xy)=log|x|+log|C|⇒tan−1(xy)=log|xC|⇒(xy)=tan(log|xC|)