The solution of the differential equation 3xy1−3y+x2−y21/2=0 satisfying the condition y(1)=1 is
3cos-1(y/x)=lnx
3cos(y/x)=lnx
3cos-1(y/x)=2logx
3sin-1(y/x)=lnx
−dydx=3y−x2−y23x, put y=vxdydx=v+xdvdx∫31−v2dv=−∫dxx⇒3cos−1(y/x)=log|x|+cPass_(1,1)_⇒c=0