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Questions  

 The solution of differential equation ydx1+exy2dy=0 is 

a
eyx=y+c
b
ex=y2+cy
c
ey=y2+cx
d
ex=y2+cx

detailed solution

Correct option is B

ydx−dy=e−xy2dyex(ydx−dy)y2=dy⇒dexy=dy integrations both sides ex=y2+cy

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