Q.
The solution of differential equation ydx−1+e−xy2dy=0 is
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a
eyx=y+c
b
ex=y2+cy
c
ey=y2+cx
d
ex=y2+cx
answer is B.
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Detailed Solution
ydx−dy=e−xy2dyex(ydx−dy)y2=dy⇒dexy=dy integrations both sides ex=y2+cy
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