Q.

The solution of differential equation ydx−1+e−xy2dy=0 is

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a

eyx=y+c

b

ex=y2+cy

c

ey=y2+cx

d

ex=y2+cx

answer is B.

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Detailed Solution

ydx−dy=e−xy2dyex(ydx−dy)y2=dy⇒dexy=dy integrations both sides ex=y2+cy
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