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Questions  

The solution of the differential equation, ydx+x+x2ydy=0  is

a
logy=cx
b
1xy+logy=c
c
−1xy+logy=c
d
−1xy+logx=c

detailed solution

Correct option is C

Given differential equation isydx+x+x2ydy=0 or ydx+xdy+x2ydy=0⇒ydx+xdyx2y+dy=0⇒ydx+xdyx2y2+dyy=0⇒dyy=−(xy)−2d(xy)⇒d(ln⁡y)=d(xy)−1 Integrate we get ⇒ln⁡y=1xy+c

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