The solution of the differential equation, y dx+x+x2ydy=0 is
logy=cx
1xy+logy=c
−1xy+logy=c
−1xy+logx=c
Given differential equation is
ydx+x+x2ydy=0 or ydx+xdy+x2ydy=0⇒ydx+xdyx2y+dy=0⇒ydx+xdyx2y2+dyy=0⇒dyy=−(xy)−2d(xy)⇒d(lny)=d(xy)−1 Integrate we get ⇒lny=1xy+c