The solution of the differential equation, y dx+x+x2ydy=0  is

Given differential equation isydx+x+x2ydy=0 or ydx+xdy+x2ydy=0⇒ydx+xdyx2y+dy=0⇒ydx+xdyx2y2+dyy=0⇒dyy=−(xy)−2d(xy)⇒d(ln⁡y)=d(xy)−1 Integrate we get ⇒ln⁡y=1xy+c