The solution of the differential equation y2dy=xxdy−ydxex/y is
exyxy−1+logy=c
ex/yx/y−1+logy=c
ey/xy/x−1+logx=c
none
The given equation can be re written as
⇒y2−x2ex/ydy=−xyex/ydx⇒dxdy=x2ex/y−y2xyex/y=xy-1xyex/y Put x=vy then ⇒dxdy=v+ydvdy⇒v+ydvdy=v−1vev
⇒∫vevdv=−∫dyy⇒ev(v−1)=−ln|y|+c⇒ex/yxy−1+lny=c