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Questions  

The solution of the differential equation y2dy=xxdyydxex/y is

a
exyxy−1+logy=c
b
ex/yx/y−1+logy=c
c
ey/xy/x−1+logx=c
d
none

detailed solution

Correct option is B

The given equation can be re written as ⇒y2−x2ex/ydy=−xyex/ydx⇒dxdy=x2ex/y−y2xyex/y=xy-1xyex/y Put x=vy then ⇒dxdy=v+ydvdy⇒v+ydvdy=v−1vev⇒∫vevdv=−∫dyy⇒ev(v−1)=−ln⁡|y|+c⇒ex/yxy−1+ln⁡y=c

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