The solution of the differential equation y+sinx.cos2xycos2xydx+xcos2xy+sinydy=0 is
tanxy+cosx+cosy=c
tanxy−cosx−cosy=c
tanxy+cosx−cosy=c
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Given equation can be rearranged as
ydx+xdycos2(xy)+sinxdx+sinydy=0 ⇒d(xy)cos2(xy)+sinxdx+sinydy=0∫ sec2xydxy+∫sin x dx +∫sin y dy =0 ⇒tanxy−cosx−cosy=c