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Questions  

Solution of the differential equation yxdydx=ay2+dydx

a
x+a1−ay=cy
b
x−a1−ay=cy
c
x−a1−ay=cx
d
none

detailed solution

Correct option is A

We have y−xdydx=ay2+dydx⇒ydx−xdy=ay2dx+ady⇒y(1−ay)dx=(x+a)dy⇒dxx+a−dyy(1−ay)=0 since 1y1-ay=1y+a1-ay Integrating , we getlog⁡(x+a)-log⁡y-alog⁡(1−ay)-a=log⁡clog (x+a)-log y+log(1-ay)=logc⇒log⁡(a+x)(1−ay)y=log⁡c⇒(x+a)(1−ay)=cy

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