A solution of the differential equation yxy−1dx+xylnxdy=0, when y2=1 is
yx=1
xy+1=0
1y=log2x
x=log2y
yxy−1+xylogxdy=0⇒dxy=0⇒∫dxy=∫0dx⇒xy=cy(2)=1⇒c=2xy=2⇒ylnx=ln2 ⇒1y=log2x