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Questions  

 Solution of the differential equation 1+y+x2ydx+x+x3dy=0 is 

a
xy=-tan−1x+c
b
x2y=-tan−x+c
c
xy2=tan−1x+c
d
xy2=cot−1x+c

detailed solution

Correct option is A

1+y1+x2+x1+x2dydx=0dydx+1xy=−1x1+x2 I.F=∫1xdx=x. Sol.is y⋅x=∫x−1x1+x2dx=−tan−1x+c

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