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Q.

Solution of the differential equation 1+y+x2ydx+x+x3dy=0 is

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a

xy=-tan−1x+c

b

x2y=-tan−x+c

c

xy2=tan−1x+c

d

xy2=cot−1x+c

answer is A.

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Detailed Solution

1+y1+x2+x1+x2dydx=0dydx+1xy=−1x1+x2 I.F=∫1xdx=x. Sol.is y⋅x=∫x−1x1+x2dx=−tan−1x+c
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