Solution of the differential equation 1+y+x2ydx+x+x3dy=0 is
xy=-tan−1x+c
x2y=-tan−x+c
xy2=tan−1x+c
xy2=cot−1x+c
1+y1+x2+x1+x2dydx=0dydx+1xy=−1x1+x2 I.F=∫1xdx=x. Sol.is y⋅x=∫x−1x1+x2dx=−tan−1x+c