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Questions  

 The solution of the differential yxy+2x2y2dx+xxyx2y2dy=0 is given by 

a
2logx-logy-1xy=c
b
2logy-logx-1xy=c
c
2logx+logy+1xy=c
d
2logy+logx+1xy=c

detailed solution

Correct option is A

xy(ydx+xdy)+x2y2(2ydx-xdy)=0÷by x3y3⇒∫d(xy)x2y2+∫2xdx−1ydy=∫0⇒−1xy+2log⁡|x|−log⁡|y|=c

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