The solution of the differential yxy+2x2y2dx+xxy−x2y2dy=0 is given by
2logx-logy-1xy=c
2logy-logx-1xy=c
2logx+logy+1xy=c
2logy+logx+1xy=c
xy(ydx+xdy)+x2y2(2ydx-xdy)=0
÷by x3y3⇒∫d(xy)x2y2+∫2xdx−1ydy=∫0⇒−1xy+2log|x|−log|y|=c