Questions
Solution of the equation are
detailed solution
Correct option is B
Putting ex−1=t2, we have exdx=2t dtso ∫log2x dxex−1=∫1ex−1 2tdttt2+1=2∫1ex−1 dtt2+1=2tan−1ex−1−π4Thus the given equation reduces totan−1ex−1−π4=π12⇒ex−1=tanπ3=3so ex=4⇒x=2log2Similar Questions
is equal to
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