Solution of the equation tancos−1x=sincot−112 is
x=±73
x=±53
x=±352
none of these
We have, tancos−1x=sincot−112
⇒tantan−11−x2x=sintan−12⇒tantan−11−x2x=sinsin−121+4⇒tantan−11−x2x=sinsin−125⇒1−x2x=25⇒51−x2=4x2⇒9x2=5,∴x=±53.