A solution of the equation tan−1(1+x)+tan−1(1−x)=π2, is
x=1
x=-1
x=0
x=π
We have,
tan−1(1+x)+tan−1(1−x)=π2⇒ tan−1(1+x)=π2−tan−1(1−x)
⇒ tan−1(1+x)=cot1(1−x)⇒ tan−1(1+x)=tan−111−x⇒ 1+x=11−x⇒1−x2=1⇒x=0