The solution of the equation 2z=|z|+2i , where z is a complex number, is -
z=33-i
z=33+i
z=33±i
None of these
2(x+iy)=x2+y2+2i2x=x2+y2 and 2y=2 ⇒y=14x2=x2+1 ⇒3x2=1 i.e., x=±13x=13(∵x≥0) ∴z=13+i=33+i