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Questions  

 The solution of the inequality |x+2||x|8x30 is 

a
[−1,2)
b
[1,2]
c
[−1,1]
d
[0,43)

detailed solution

Correct option is A

|x+2|−|x|8−x3≥0 We must have 8−x3>0⇒ x3<8⇒x<2 Also |x+2|−|x|≥0⇒ |x+2|≥|x|⇒(x+2)2−x2≥0⇒2(x+1)≥0⇒ x≥−1 So x∈[−1,2)

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