The solution set of the equation pqx2−(p+q)2x+(p+q)2=0 is
pq,qp
pq,pq
qp,pq
p+qp,p+qq
The given equation is pqx2−(p+q)2x+(p+q)2=0x=(p+q)2±(p+q)4−4pq(p+q)22pqx=(p+q)2±p2−q22pqNow, taking (+ ve) signx=p+qq ∴solution set is p+qp,p+qq