The solution set of the equationpqx2-(p+q)2x+(p+q)2=0 is

Given equation (pq)x2-(p+q)2x+(p+q)2=0Let solution set is p+qp,p+qqSum of roots =(p+q)2pq⇒p+qp+p+qq=(p+q)2pqSimilarly, product of roots =(p+q)2pq⇒p+qp×p+qq=(p+q)2pq.