The solution set of the equation sinπx23=x2−23x+4

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Forms an empty set

is having only one element

is having only two elements

is having greater than two elements

answer is B.

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Detailed Solution

We have sinπx23=x2−23x+4.Since −1≤sinπx23≤1,⇒−1≤x2−23x+4≤1⇒ x2−23x+3≤0⇒ x−32≤0 But x−32≥0 ⇒x−32=0⇒ x=3

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