The solution set of equations cos5x=1+sin4xis
2nπ,n∈Ι
nπ2,n∈Ι
4nπ,n∈Ι
nπ,n∈Ι
cos5x=1+sin4x
Minimum value of R.H.S is 1
and maximum value of L.H.S is 1.
so equality holds only when both sides are simultaneously equal and equal to 1.
⇒ cosx=1 and sinx=0⇒ cosx=1⇒x=2nπ and sinx=0⇒x=nπ So, solution set is x=2nπ, n∈I