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$Solution set of inequality \log_{1 / 2} x + \log_{3} x > 1 is$

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x<21log3⁡2−1

x<31log3⁡2−1

x>21log3⁡2−1

x<31log2⁡3−1

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detailed solution

Correct option is A

log1/2⁡x+log3⁡x>1⇒ −log2⁡x+log3⁡x>1⇒ log3⁡x>1+log2⁡x⇒ log2⁡xlog2⁡3>1+log2⁡x⇒ 1log2⁡3−1log2⁡x>1⇒ log2⁡x<1log3⁡2−1⇒ 0

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Solution set of inequality log1/2⁡x+log3⁡x>1 is

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$Solution set of inequality \log_{1 / 2} x + \log_{3} x > 1 is$