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a
(1,∞)
b
0,log2(4/3)
c
(-1,∞)
d
0,log2(4/3)∪(1,∞)
answer is D.
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Detailed Solution
Put 2x=t. Then t>0. The given inequality becomes 1t−1>22−t⇒1t−1−22−t>0⇒2−t−2t+2(t−1)(2−t)>0⇒4−3t(t−1)(2−t)>0⇒(t−1)(t−4/3)(t−2)>0.From above sign scheme, we get 12. ⇒ 1<2x<4/3 or 2x>2⇒ 01