Solution set of the inequality 12x−1>11−2x−1 is

Put 2x=t. Then t>0. Now, given inequality becomes 1t−1>22−t⇒1t−1−22−t>0⇒2−t−2t+2(t−1)(2−t)>0⇒4−3t(t−1)(2−t)>0⇒t−43(t−1)(t−2)>0.     From sign scheme, we get12.⇒ 1<2x<43 or 2x>2⇒ x∈0,log2⁡43∪(1,∞)