Solution set of the inequations x2−4x≤12 and x2−2x≥15 taken together is
(5,6)
[5,6]
[−3,5]
[2,5].
The given inequations are x2−4x ≤ 12 ⇒ x2−4x−12 ≤0
⇒ (x−6) (x+2) ≤0 ⇒ x∈ [−2,6] ….. ( 1 )
And x2−2x≥ 15 ⇒ x2−2x−15 ≥0
⇒ (x−5)(x+3)≥0
⇒ x≤−3 or x≥5
⇒ x∈ (−∞,−3]∪[5,∞) …… ( 2 )
∴ Solution set of the inequations is [−2,6]∩(−∞,−3]∪ [5,∞)= [5,6]