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Q.

The solution set of sin2θ=−12 is

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a

{nπ2+(−1)n+1π6:n∈Z}

b

{nπ2+(−1)nπ12:n∈Z}

c

{nπ3+(−1)n2π15:n∈Z}

d

{nπ2+(−1)n+1π8:n∈Z}

answer is D.

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Detailed Solution

sin2θ=−12=sin-π4⇒2θ=nπ+-1n-π4 ⇒θ=nπ2+-1n+1π8
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The solution set of sin2θ=−12 is