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Solution set of is given by
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a
3
b
7p-3: p∈Z
c
7p+3: p∈Z
d
None of these
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Correct option is C
x=3(mod 7)⇒x-3=7p, (p∈z)⇒x=7p+3, p∈z i.e., 7p+3: p∈z.
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