First slide

Theory of equations

Question

Solution set of $\frac{x^{2} - 1}{x^{2} + 1} > 0$ is

Moderate

A

$(- 1, 1)$
B

$[- 1, 1]$
C

$(- \infty, - 1) \cup (1, \infty)$
D

None of these

Solution

Given inequation is $\frac{x^{2} - 1}{x^{2} + 1} > 0$
$\Rightarrow x^{2} - 1 > 0 \Rightarrow x^{2} > 1.$ $(∵ x^{2} + 1 > 0; \forall x \in R)$

The solution set is $(- \infty, - 1) \cup (1, \infty)$

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