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$The solution set of x^{2} + 2 \leq 3 x \leq 2 x^{2} - 5 is$

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(−∞,−1]∪52,∞

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Solve the inequationsx2−3x+2≤0 and 2x2−3x−5≥0⇒x-1x-2≤0 and 2x-5x+1≥0⇒ 1≤x≤2 and x≤−1 or x≥52 The intersection of the two intervals is ϕ

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The solution set of x2+2≤3x≤2x2−5 is

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$The solution set of x^{2} + 2 \leq 3 x \leq 2 x^{2} - 5 is$