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Q.

The solution of 4sin2⁡ x+tan2⁡ x+cosec2⁡ x+cot2⁡ x−6=0 is (n∈Z)

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a

nπ±π4

b

2nπ±π4

c

nπ+π3

d

nπ−π6

answer is A.

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Detailed Solution

(2sin ⁡x−cosec ⁡x)2+(tan ⁡x−cot⁡ x)2=0⇒ sin2⁡ x=12 and tan2⁡ x=1⇒ x=nπ±π4,n∈Z

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