The solution of 4sin2 x+tan2 x+cosec2 x+cot2 x−6=0 is (n∈Z)
nπ±π4
2nπ±π4
nπ+π3
nπ−π6
(2sin x−cosec x)2+(tan x−cot x)2=0⇒ sin2 x=12 and tan2 x=1⇒ x=nπ±π4,n∈Z