The solution of sin⁡xy(ydx−xdy)=xy3(xdy+ydx) is

Given differential equation issin⁡xy(ydx−xdy)=xy3(xdy+ydx)⇒sin⁡xyydx−xdyy2=xy(xdy+ydx)⇒d−cos⁡xy=12d(xy)2⇒−cos⁡xy=12(xy)2⇒−cos⁡xy=12(xy)2+c⇒xy22+cosxy+c=0