Q.

The solution of the system of equations whose augmented matrix 1112123131-54 is

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a

x=3,   y=1,   z=1

b

x=4,   y=−3,   z=1

c

x=1,   y=1,   z=1

d

x=7,   y=−10,   z=4

answer is B.

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Detailed Solution

1112123131-54~1112012-10-2-8-2   R2→R2-R1, R3→R3-3R1                      ~10-13012-100-4-4     R1→R1-R2, R3→R3+2R2                      ~40016020-600-4-4      R1→4R1-R3, R2→2R2+R3 ⇒the given system is equivalent to 4x=16, 2y=-6 and -4z=-4. ⇒x=4, y=-3 and z=1
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