The solution of the system of equations whose augmented matrix 1112123131-54 is
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a
x=3, y=1, z=1
b
x=4, y=−3, z=1
c
x=1, y=1, z=1
d
x=7, y=−10, z=4
answer is B.
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Detailed Solution
1112123131-54~1112012-10-2-8-2 R2→R2-R1, R3→R3-3R1 ~10-13012-100-4-4 R1→R1-R2, R3→R3+2R2 ~40016020-600-4-4 R1→4R1-R3, R2→2R2+R3 ⇒the given system is equivalent to 4x=16, 2y=-6 and -4z=-4. ⇒x=4, y=-3 and z=1