Q.

Solution of the system of equations  2x+3y+10z=4,4x−6y+5z=1,6x+9y−20z=2, (x,y,z)=

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a

(1, 2, 3)

b

( 2, 3, 5)

c

( 3, 2, 5)

d

( 5, 3, 2)

answer is B.

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Detailed Solution

Augmented matrix=231044-65169-202                                      R2→R2-2R1, R3→R3-3R1                                   ~231040-12-15-700-50-10 This is equivalent to the system of equations 2x+3y+10z=4, -12y-15z=-7, -50z=-10 Solving the above we get, z=5, y=3 and x=2. ∴x,y,z=2,3,5
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