The solution of $$tan$$⁡$$x+$$$$tan$$⁡$$2x+$$$$tan$$⁡$$3x=$$$$tan$$⁡xtan⁡$$2xtan$$⁡$$3x$$ is

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The solution of $$tan$$⁡$$x+$$$$tan$$⁡$$2x+$$$$tan$$⁡$$3x=$$$$tan$$⁡xtan⁡$$2xtan$$⁡$$3x$$ is

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we know that,  $$tan$$⁡$$3x=$$$$tan$$⁡(x+2x)=$$$$tan$$⁡$$x+$$$$tan$$⁡$$2x1$$−$$tan$$⁡xtan⁡$$2x$$⇒    $$tan$$⁡$$3x$$−$$tan$$⁡xtan⁡$$2xtan$$⁡$$3x=$$$$tan$$⁡$$x+$$$$tan$$⁡$$2x$$⇒    $$tan$$⁡xtan⁡$$2xtan$$⁡$$3x=$$$$tan$$⁡$$3x$$−$$tan$$⁡x−$$tan$$⁡$$2x$$… $$(i)  Now,     $$tan$$⁡$$x+$$$$tan$$⁡$$2x+$$$$tan$$⁡$$3x=$$$$tan$$⁡xtan⁡$$2xtan$$⁡$$3x$$⇒    $$tan$$⁡$$x+$$$$tan$$⁡$$2x+$$$$tan$$⁡$$3x=$$$$tan$$⁡$$3x$$−$$tan$$⁡x−$$tan$$⁡$$2x$$⇒    [ from Eq. (i)] ⇒    $$2x=n$$π$$+($$−$$x)$$⇒$$3x=n$$π⇒    $$x=n$$$$π$$$$3$$, where n∈I

The solution of $\tan x + \tan 2 x + \tan 3 x = \tan xtan 2 xtan 3 x$ is

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The solution of tan⁡x+tan⁡2x+tan⁡3x=tan⁡xtan⁡2xtan⁡3x is

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The solution of $\tan x + \tan 2 x + \tan 3 x = \tan xtan 2 xtan 3 x$ is