First slide

Introduction to Differential equations

Question

$The solution of x \log x \frac{d y}{d x} + y = 2 \log x is$

Easy

A

${ylogx=(logx)}^{2} -x+c$
B

${ylogx=(logx)}^{2} +c$
C

${ylogx=(logy)}^{2} +c$
D

${xlogy=(logx)}^{2} +c$

Solution

$\begin{array}{l} I . F = e^{\int \frac{1}{x \log x} d x} = e^{\log (\log x)} = \log x \\ Solution of the differential equation is ylog x = (\log x)^{2} + c \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App