The solution of xlog⁡$$xdydx+y=2log$$⁡x is

Correct option is 2ylogx=(logx)2+c

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$The solution of x \log x \frac{d y}{d x} + y = 2 \log x is$

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ylogx=(logx)2-x+c

ylogx=(logx)2+c

ylogx=(logy)2+c

xlogy=(logx)2+c

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detailed solution

Correct option is B

I.F=e∫1xlog⁡xdx=elog⁡(log⁡x)=log⁡x Solution of the differential equation is ylog⁡x=(log⁡x)2+c

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The solution of xlog⁡xdydx+y=2log⁡x is

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$The solution of x \log x \frac{d y}{d x} + y = 2 \log x is$