First slide

Introduction to sets

Question

$Solution of |\frac{1}{x} - 2| < 4 is$

Easy

A

$(- \infty, - \frac{1}{2})$
B

$(\frac{1}{6}, \infty)$
C

$(- \frac{1}{2}, \frac{1}{6})$
D

$(- \infty, - \frac{1}{2})$ $\cup$ $(\frac{1}{6}, \infty)$

Solution

$\begin{array}{l} |\frac{1}{x} - 2| < 4 \\ \Leftrightarrow - 4 < \frac{1}{x} - 2 < 4 \\ \Leftrightarrow - 2 < \frac{1}{x} < 6 \\ Hence x \in (- \infty, - \frac{1}{2}) \cup (\frac{1}{6}, \infty) \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App