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The solution of 8x6(mod14) is where [a]={a+14k:kI}

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a
[8], [6]
b
[6], [14]
c
[6], [13]
d
[8], [14], [16]

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detailed solution

Correct option is C

We need to solve 14∣(8x−6) i.e., 8x−6=14k, for k ∈ I. The values 6 and 13 satisfy this equation,while 8, 14 and 16 do not.


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