The solution of (6x+7y−4)dx+(7x−4y+3)dy=0 is
3x2+7xy−2y2−4x+3y=c
6x2−4y2+7xy−4x+3y=c
3x2+14xy−4y2−4x+3y=c
6x2+4x−4y2+4x+3y=c
G.E ⇒6∫xdx−4∫ydy+7∫d(xy)−4∫dx+3∫dy=c