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Q.

The solution of (6x+7y−4)dx+(7x−4y+3)dy=0 is

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a

3x2+7xy−2y2−4x+3y=c

b

6x2−4y2+7xy−4x+3y=c

c

3x2+14xy−4y2−4x+3y=c

d

6x2+4x−4y2+4x+3y=c

answer is A.

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Detailed Solution

G.E ⇒6∫xdx−4∫ydy+7∫d(xy)−4∫dx+3∫dy=c
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