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Questions  

 The solution of (6x+7y4)dx+(7x4y+3)dy=0 is 

a
3x2+7xy−2y2−4x+3y=c
b
6x2−4y2+7xy−4x+3y=c
c
3x2+14xy−4y2−4x+3y=c
d
6x2+4x−4y2+4x+3y=c

detailed solution

Correct option is A

G.E ⇒6∫xdx−4∫ydy+7∫d(xy)−4∫dx+3∫dy=c

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