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Q.

Solution of xy4+ydx−xdy=0 is

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a

x44+xy3=c

b

x44+13xy3=c

c

x44+3xy2=c

d

x44−13xy3=c

answer is B.

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Detailed Solution

xy4+ydx=xdy dydx=xy4+yxdydx=yx=y41y4dydx−1y31x=1 substitute 1y3=v-1y3=v⇒3y4dydx=dvdxdvdx+3xv=3 IF=e∫3xdx=x3GS. is v IF =∫Q IFdx-x3y3=3∫x3dx⇒-xy3+c=34x4

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