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Questions  

 The solution of y3cosxdxxe1/y2dy=0 is 

a
e1/y2+2sin⁡x=c
b
e1/y2+4sinx=c
c
e1/y2-2sinx=c
d
e1/y2-4sinx=c

detailed solution

Correct option is B

∫cos⁡xxdx=−12∫e1/y2−2/y3dy⇒2sin⁡x=−12e1/y2+c⇒e1/y2+4sin⁡x=c

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The general solution of the differential equation 1+y2dx+1+x2dy=0 is


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