The solution of y3cosxdx−xe1/y2dy=0 is
e1/y2+2sinx=c
e1/y2+4sinx=c
e1/y2-2sinx=c
e1/y2-4sinx=c
∫cosxxdx=−12∫e1/y2−2/y3dy⇒2sinx=−12e1/y2+c⇒e1/y2+4sinx=c