The solution of ydx−xdy+3x2y2ex3dx=0 is
yx+ex3=c
xy-ex3=c
xy+ex3=c
yx-ex3=c3
∫ydx-xdyy2+∫3ex3.x2dx
⇒∫d(x/y)+∫ex3⋅3x2dx⇒xy+ex3=c