Solve sin2x+cos2y=2sec2z for x,yand z
x=(2m+1)π2,m∈Z
y=nπ,n∈Z
z=tπ,t∈Z
All the above
LHS=sin2x+cos2y≤2, sin2x≤1,cos2y≤1
RHS=2sec2z≥2
LHS=RHS only when sin2x=1,cos2y=1,2sec2z=2
⇒cos2x=0,sin2y=0,cos2z=1
⇒cosx=0,siny=0,sinz=0
⇒x=(2m+1)π2,y=nπ and z=tπ, m,n,t∈Z